2x/x+3-2=x+2/x-3

Solution for 2x/x+3-2=x+2/x-3 equation:

2x/x+3-2=x+2/x-3

We move all terms to the left:

2x/x+3-2-(x+2/x-3)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: x-3)!=0

x∈R


We add all the numbers together, and all the variables

2x/x-(x+2/x-3)+1=0

We get rid of parentheses

2x/x-x-2/x+3+1=0

We multiply all the terms by the denominator


2x-x*x+3*x+1*x-2=0

We add all the numbers together, and all the variables

6x-x*x-2=0

Wy multiply elements

-1x^2+6x-2=0

a = -1; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·(-1)·(-2)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{7}}{2*-1}=\frac{-6-2\sqrt{7}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{7}}{2*-1}=\frac{-6+2\sqrt{7}}{-2}
$