2x/x+4-2=x-16/x-4

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Solution for 2x/x+4-2=x-16/x-4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/x-2+4 = x-(16/x)-4 // - x-(16/x)-4

16/x-x+(2*x)/x-2+4+4 = 0

16*x^-1-1*x^1+8*x^0 = 0

(8*x^1-1*x^2+16*x^0)/(x^1) = 0 // * x^2

x^1*(8*x^1-1*x^2+16*x^0) = 0

x^1

8*x-x^2+16 = 0

8*x-x^2+16 = 0

DELTA = 8^2-(-1*4*16)

DELTA = 128

DELTA > 0

x = (128^(1/2)-8)/(-1*2) or x = (-128^(1/2)-8)/(-1*2)

x = (8*2^(1/2)-8)/(-2) or x = (-8*2^(1/2)-8)/(-2)

x in { (8*2^(1/2)-8)/(-2), (-8*2^(1/2)-8)/(-2)} 

x in { (8*2^(1/2)-8)/(-2), (-8*2^(1/2)-8)/(-2) }

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