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2x/x-3=x-2/x-5
We move all terms to the left:
2x/x-3-(x-2/x-5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-5)!=0We get rid of parentheses
x∈R
2x/x-x+2/x+5-3=0
We multiply all the terms by the denominator
2x-x*x+5*x-3*x+2=0
We add all the numbers together, and all the variables
4x-x*x+2=0
Wy multiply elements
-1x^2+4x+2=0
a = -1; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·(-1)·2
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{6}}{2*-1}=\frac{-4-2\sqrt{6}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{6}}{2*-1}=\frac{-4+2\sqrt{6}}{-2} $
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