2x2+-10=40

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Solution for 2x2+-10=40 equation: 



2x^2+-10=40

We move all terms to the left:

2x^2+-10-(40)=0

determiningTheFunctionDomain
2x^2-10-40+=0

We add all the numbers together, and all the variables

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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