2x2+10=1162

Solution for 2x2+10=1162 equation:

2x^2+10=1162

We move all terms to the left:

2x^2+10-(1162)=0

We add all the numbers together, and all the variables

2x^2-1152=0

a = 2; b = 0; c = -1152;
Δ = b2-4ac
Δ = 02-4·2·(-1152)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*2}=\frac{-96}{4}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*2}=\frac{96}{4}
=24
$