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2x^2+12x+20=2
We move all terms to the left:
2x^2+12x+20-(2)=0
We add all the numbers together, and all the variables
2x^2+12x+18=0
a = 2; b = 12; c = +18;
Δ = b2-4ac
Δ = 122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-12}{4}=-3$
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