2x2+150=4200

Solution for 2x2+150=4200 equation:

2x^2+150=4200

We move all terms to the left:

2x^2+150-(4200)=0

We add all the numbers together, and all the variables

2x^2-4050=0

a = 2; b = 0; c = -4050;
Δ = b2-4ac
Δ = 02-4·2·(-4050)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*2}=\frac{-180}{4}
=-45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*2}=\frac{180}{4}
=45
$