2x2+15=465

Solution for 2x2+15=465 equation:

2x^2+15=465

We move all terms to the left:

2x^2+15-(465)=0

We add all the numbers together, and all the variables

2x^2-450=0

a = 2; b = 0; c = -450;
Δ = b2-4ac
Δ = 02-4·2·(-450)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*2}=\frac{-60}{4}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*2}=\frac{60}{4}
=15
$