2x2+15x=8

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Solution for 2x2+15x=8 equation:



2x^2+15x=8
We move all terms to the left:
2x^2+15x-(8)=0
a = 2; b = 15; c = -8;
Δ = b2-4ac
Δ = 152-4·2·(-8)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-17}{2*2}=\frac{-32}{4} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+17}{2*2}=\frac{2}{4} =1/2 $

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