2x2+16x+30=0

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Solution for 2x2+16x+30=0 equation: 



2x^2+16x+30=0

a = 2; b = 16; c = +30;
Δ = b2-4ac
Δ = 162-4·2·30
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*2}=\frac{-20}{4}
=-5
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*2}=\frac{-12}{4}
=-3
$

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