2x2+17x+36=0

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Solution for 2x2+17x+36=0 equation:



2x^2+17x+36=0
a = 2; b = 17; c = +36;
Δ = b2-4ac
Δ = 172-4·2·36
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-1}{2*2}=\frac{-18}{4} =-4+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+1}{2*2}=\frac{-16}{4} =-4 $

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