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2x^2+17x-15=0
a = 2; b = 17; c = -15;
Δ = b2-4ac
Δ = 172-4·2·(-15)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{409}}{2*2}=\frac{-17-\sqrt{409}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{409}}{2*2}=\frac{-17+\sqrt{409}}{4} $
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