If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+19x+9=0
a = 2; b = 19; c = +9;
Δ = b2-4ac
Δ = 192-4·2·9
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-17}{2*2}=\frac{-36}{4} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+17}{2*2}=\frac{-2}{4} =-1/2 $
| 2=3x=19/5 | | 2x+7-24=100+4x | | 5(x-2)+6x=7x+4(x-6) | | s/9+26=29 | | –11g=18−20g | | N2/5+2n/6=12 | | (5x-15)+(8x-8)=180 | | 16d=14d+18 | | m/7+40=46 | | 186-w=232 | | 6(9+x)=54 | | 9000m=2700 | | 2x2+x+1=0 | | 5s-4s=17 | | 16=b/7+13 | | 7x–10x=9 | | b+13/4=9 | | -(18-4x)=18 | | 17x=-51;x=-3 | | 85=9d+4 | | 9(k+1)=90 | | 5^n=5^11⋅5^3 | | 4x=4x-4+2x | | 5^n=56^11⋅5^3 | | -19+8s=-91 | | 2x+6=×+10 | | -2x4+8x2=0 | | 14x=56;x=6 | | 9x+5x=(-28) | | 20x-40=30x | | -16=8(t-96) | | v-9+15=0 |