2x2+200x-3200=0

Solution for 2x2+200x-3200=0 equation:

2x^2+200x-3200=0

a = 2; b = 200; c = -3200;
Δ = b2-4ac
Δ = 2002-4·2·(-3200)
Δ = 65600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{65600}=\sqrt{1600*41}=\sqrt{1600}*\sqrt{41}=40\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-40\sqrt{41}}{2*2}=\frac{-200-40\sqrt{41}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+40\sqrt{41}}{2*2}=\frac{-200+40\sqrt{41}}{4}
$