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2x^2+21x-23=0
a = 2; b = 21; c = -23;
Δ = b2-4ac
Δ = 212-4·2·(-23)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-25}{2*2}=\frac{-46}{4} =-11+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+25}{2*2}=\frac{4}{4} =1 $
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