2x2+24=x2-11x

Solution for 2x2+24=x2-11x equation:

2x^2+24=x2-11x

We move all terms to the left:

2x^2+24-(x2-11x)=0

We add all the numbers together, and all the variables

2x^2-(+x^2-11x)+24=0

We get rid of parentheses

2x^2-x^2+11x+24=0

We add all the numbers together, and all the variables

x^2+11x+24=0

a = 1; b = 11; c = +24;
Δ = b2-4ac
Δ = 112-4·1·24
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*1}=\frac{-16}{2}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*1}=\frac{-6}{2}
=-3
$