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2x^2+26x+44=0
a = 2; b = 26; c = +44;
Δ = b2-4ac
Δ = 262-4·2·44
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-18}{2*2}=\frac{-44}{4} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+18}{2*2}=\frac{-8}{4} =-2 $
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