2x2+28=x2+11x

Solution for 2x2+28=x2+11x equation:

2x^2+28=x2+11x

We move all terms to the left:

2x^2+28-(x2+11x)=0

We add all the numbers together, and all the variables

2x^2-(+x^2+11x)+28=0

We get rid of parentheses

2x^2-x^2-11x+28=0

We add all the numbers together, and all the variables

x^2-11x+28=0

a = 1; b = -11; c = +28;
Δ = b2-4ac
Δ = -112-4·1·28
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-3}{2*1}=\frac{8}{2}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+3}{2*1}=\frac{14}{2}
=7
$