2x2+2x=4

Solution for 2x2+2x=4 equation:

2x^2+2x=4

We move all terms to the left:

2x^2+2x-(4)=0

a = 2; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·2·(-4)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6}{2*2}=\frac{4}{4}
=1
$