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2x^2+30x=68
We move all terms to the left:
2x^2+30x-(68)=0
a = 2; b = 30; c = -68;
Δ = b2-4ac
Δ = 302-4·2·(-68)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-38}{2*2}=\frac{-68}{4} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+38}{2*2}=\frac{8}{4} =2 $
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