2x2+32x+-150=0

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Solution for 2x2+32x+-150=0 equation:



2x^2+32x+-150=0
We add all the numbers together, and all the variables
2x^2+32x=0
a = 2; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·2·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*2}=\frac{-64}{4} =-16 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*2}=\frac{0}{4} =0 $

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