2x2+32x=72

Solution for 2x2+32x=72 equation:

2x^2+32x=72

We move all terms to the left:

2x^2+32x-(72)=0

a = 2; b = 32; c = -72;
Δ = b2-4ac
Δ = 322-4·2·(-72)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-40}{2*2}=\frac{-72}{4}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+40}{2*2}=\frac{8}{4}
=2
$