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2x^2+34x-336=0
a = 2; b = 34; c = -336;
Δ = b2-4ac
Δ = 342-4·2·(-336)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-62}{2*2}=\frac{-96}{4} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+62}{2*2}=\frac{28}{4} =7 $
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