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2x^2+37x+48=0
a = 2; b = 37; c = +48;
Δ = b2-4ac
Δ = 372-4·2·48
Δ = 985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{985}}{2*2}=\frac{-37-\sqrt{985}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{985}}{2*2}=\frac{-37+\sqrt{985}}{4} $
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