If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+3x=7
We move all terms to the left:
2x^2+3x-(7)=0
a = 2; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·2·(-7)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{65}}{2*2}=\frac{-3-\sqrt{65}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{65}}{2*2}=\frac{-3+\sqrt{65}}{4} $
| -9x-10=-37 | | 14k-126=42 | | 4(3x+1)=40+x | | -60=-12r | | d–112=512 | | ½(x+8)–15=-3 | | -7-13u=11-4u | | 98=7(n-5) | | 532=y-36 | | k/11+16=82 | | 63=9(z+3) | | 5=-7+4n | | 10+6y=-44 | | 7=d/3-3 | | 3x-3=1x-1 | | -4-5z=2+10 | | 71=u/9-65 | | 6.6=w–1.2 | | 12(6+2y)=4y-(5-9y) | | 8p+13=37 | | 15x+8=98 | | 15=3(n+10) | | -3+x/2=-2 | | /2(8x+20=18 | | 4(m+-7)=-7 | | (x-3)+110+130+x=360 | | 8c+12–10c=–2 | | 4x+3(x-12)=-22+5x | | a–3.2=5.5 | | -2=4+3a | | 3/4(y)=18 | | 12/x=9/4 |