2x2+3x=90

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Solution for 2x2+3x=90 equation:



2x^2+3x=90
We move all terms to the left:
2x^2+3x-(90)=0
a = 2; b = 3; c = -90;
Δ = b2-4ac
Δ = 32-4·2·(-90)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-27}{2*2}=\frac{-30}{4} =-7+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+27}{2*2}=\frac{24}{4} =6 $

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