2x2+40x-7000=0

Solution for 2x2+40x-7000=0 equation:

2x^2+40x-7000=0

a = 2; b = 40; c = -7000;
Δ = b2-4ac
Δ = 402-4·2·(-7000)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-240}{2*2}=\frac{-280}{4}
=-70
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+240}{2*2}=\frac{200}{4}
=50
$