2x2+48=x2+14x

Solution for 2x2+48=x2+14x equation:

2x^2+48=x2+14x

We move all terms to the left:

2x^2+48-(x2+14x)=0

We add all the numbers together, and all the variables

2x^2-(+x^2+14x)+48=0

We get rid of parentheses

2x^2-x^2-14x+48=0

We add all the numbers together, and all the variables

x^2-14x+48=0

a = 1; b = -14; c = +48;
Δ = b2-4ac
Δ = -142-4·1·48
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*1}=\frac{12}{2}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*1}=\frac{16}{2}
=8
$