2x2+4x-510=0

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Solution for 2x2+4x-510=0 equation:



2x^2+4x-510=0
a = 2; b = 4; c = -510;
Δ = b2-4ac
Δ = 42-4·2·(-510)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-64}{2*2}=\frac{-68}{4} =-17 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+64}{2*2}=\frac{60}{4} =15 $

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