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2x^2+50=25x
We move all terms to the left:
2x^2+50-(25x)=0
a = 2; b = -25; c = +50;
Δ = b2-4ac
Δ = -252-4·2·50
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-15}{2*2}=\frac{10}{4} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+15}{2*2}=\frac{40}{4} =10 $
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