2x2+6x-2590=0

Solution for 2x2+6x-2590=0 equation:

2x^2+6x-2590=0

a = 2; b = 6; c = -2590;
Δ = b2-4ac
Δ = 62-4·2·(-2590)
Δ = 20756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20756}=\sqrt{4*5189}=\sqrt{4}*\sqrt{5189}=2\sqrt{5189}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{5189}}{2*2}=\frac{-6-2\sqrt{5189}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{5189}}{2*2}=\frac{-6+2\sqrt{5189}}{4}
$