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2x^2+6x-8=-12.5
We move all terms to the left:
2x^2+6x-8-(-12.5)=0
We add all the numbers together, and all the variables
2x^2+6x+4.5=0
a = 2; b = 6; c = +4.5;
Δ = b2-4ac
Δ = 62-4·2·4.5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-6}{4}=-1+1/2$
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