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2x^2+7=42-x
We move all terms to the left:
2x^2+7-(42-x)=0
We add all the numbers together, and all the variables
2x^2-(-1x+42)+7=0
We get rid of parentheses
2x^2+1x-42+7=0
We add all the numbers together, and all the variables
2x^2+x-35=0
a = 2; b = 1; c = -35;
Δ = b2-4ac
Δ = 12-4·2·(-35)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{281}}{2*2}=\frac{-1-\sqrt{281}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{281}}{2*2}=\frac{-1+\sqrt{281}}{4} $
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