2x2+800x-1920000=0

Solution for 2x2+800x-1920000=0 equation:

2x^2+800x-1920000=0

a = 2; b = 800; c = -1920000;
Δ = b2-4ac
Δ = 8002-4·2·(-1920000)
Δ = 16000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16000000}=4000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-4000}{2*2}=\frac{-4800}{4}
=-1200
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+4000}{2*2}=\frac{3200}{4}
=800
$