2x2+x+0.125=0

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Solution for 2x2+x+0.125=0 equation: 



2x^2+x+0.125=0

a = 2; b = 1; c = +0.125;
Δ = b2-4ac
Δ = 12-4·2·0.125
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-1}{4}=-1/4$

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