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2x^2+x-1=(2x+3)(x-1)
We move all terms to the left:
2x^2+x-1-((2x+3)(x-1))=0
We multiply parentheses ..
2x^2-((+2x^2-2x+3x-3))+x-1=0
We calculate terms in parentheses: -((+2x^2-2x+3x-3)), so:We add all the numbers together, and all the variables
(+2x^2-2x+3x-3)
We get rid of parentheses
2x^2-2x+3x-3
We add all the numbers together, and all the variables
2x^2+x-3
Back to the equation:
-(2x^2+x-3)
2x^2+x-(2x^2+x-3)-1=0
We get rid of parentheses
2x^2-2x^2+x-x+3-1=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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