If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+x-2=0
a = 2; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·2·(-2)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{17}}{2*2}=\frac{-1-\sqrt{17}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{17}}{2*2}=\frac{-1+\sqrt{17}}{4} $
| 6a=0.65 | | 12n-23n+11.5n=44 | | 2x+5-7x=16 | | 5=-5/9+v | | -3.5(2n-6)=-4.5(2n-6) | | 5(x+7)-20=6x | | x+8/x+9=2/3 | | 5+x/2=20/4 | | 6x+30-2=6(x+5)+2 | | 3(y-)=10 | | Y/12=z | | 8(x+5)=5x+10 | | 8m+12=-24 | | 3+x/3=32 | | 4(2d+5)=28 | | 8-5=2x+3 | | 23/3(6c-18)=-3/4(8c+32)-18 | | 23/3(6c-18=-(8c+32)-18 | | 889=20x+49 | | 21+2x-3=180 | | (8x^2+5x+5)-(6x^2-4x+4)=0 | | 7-3(7p-8)=136 | | 4(4y−2)+8=80 | | 10(5s+6)+8=218 | | 6(x+3)=2(3x-4) | | 3+6(6x-3)=237 | | x÷2+3x=5 | | 15y+-3=61 | | x+2x0=5 | | 2+7b=-13 | | 30=d4+2 | | 3+3x+4-40=0 |