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2x^2-10x-828=0
a = 2; b = -10; c = -828;
Δ = b2-4ac
Δ = -102-4·2·(-828)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-82}{2*2}=\frac{-72}{4} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+82}{2*2}=\frac{92}{4} =23 $
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