2x2-10x=16x-20

Solution for 2x2-10x=16x-20 equation:

2x^2-10x=16x-20

We move all terms to the left:

2x^2-10x-(16x-20)=0

We get rid of parentheses

2x^2-10x-16x+20=0

We add all the numbers together, and all the variables

2x^2-26x+20=0

a = 2; b = -26; c = +20;
Δ = b2-4ac
Δ = -262-4·2·20
Δ = 516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{516}=\sqrt{4*129}=\sqrt{4}*\sqrt{129}=2\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{129}}{2*2}=\frac{26-2\sqrt{129}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{129}}{2*2}=\frac{26+2\sqrt{129}}{4}
$