If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-126=0
a = 2; b = 0; c = -126;
Δ = b2-4ac
Δ = 02-4·2·(-126)
Δ = 1008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1008}=\sqrt{144*7}=\sqrt{144}*\sqrt{7}=12\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{7}}{2*2}=\frac{0-12\sqrt{7}}{4} =-\frac{12\sqrt{7}}{4} =-3\sqrt{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{7}}{2*2}=\frac{0+12\sqrt{7}}{4} =\frac{12\sqrt{7}}{4} =3\sqrt{7} $
| 3x²+4x+3=445 | | 3/5x20=30 | | 3/5x-20=20 | | 7x(24-96)=-72 | | 20x+15=x | | -7(y+4)=-77 | | -19=-3+4y | | X4+7x2-44=0 | | -2x^2+6+x=0 | | (X+2)(x+1)=x(x+4) | | 4x+x^2=-2+9x-x^2 | | x2-(x+1)(x+1)=5 | | -9=v/9-3 | | c=100(1+0.05)² | | 5x+2x+60-3x=120 | | 64=100/x | | 64=x/100 | | 5(n^2-5)=-20n | | 40+0.5x=45+0.4x | | 0.5x+20=0.6 | | 3=11x=25 | | 6x+10=59 | | 12x=-3(2x+6) | | M^2+10m=11 | | 43+5x=35 | | 35=5x+43 | | 2x+8=16* | | 3(20+1)=11(a-2) | | 5(x+8)+3=35 | | h/4+1=9* | | 21-7x=15+2x | | n/10-20=0* |