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2x^2-12x=8x-50
We move all terms to the left:
2x^2-12x-(8x-50)=0
We get rid of parentheses
2x^2-12x-8x+50=0
We add all the numbers together, and all the variables
2x^2-20x+50=0
a = 2; b = -20; c = +50;
Δ = b2-4ac
Δ = -202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{20}{4}=5$
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