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2x2-14x+24=0

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Solution for 2x2-14x+24=0 equation: 



2x^2-14x+24=0

a = 2; b = -14; c = +24;
Δ = b2-4ac
Δ = -142-4·2·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{4}=2


x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*2}=\frac{12}{4}
=3



x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*2}=\frac{16}{4}
=4

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