If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-16x+8=0
a = 2; b = -16; c = +8;
Δ = b2-4ac
Δ = -162-4·2·8
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{3}}{2*2}=\frac{16-8\sqrt{3}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{3}}{2*2}=\frac{16+8\sqrt{3}}{4} $
| 3x+4(2+x)=-13 | | 25x^2-6x-46=0 | | -2+7=x+3 | | 9z=6(1/2z-6) | | X+(x+4)=60 | | X-2(x-6)=-×+12 | | 150-20x=0 | | x4-36=0 | | 5x^2+19=39 | | |18-2x|=26 | | 3+4+4*15=67x | | x^2-5x+7=2x-3 | | 4x-4=-4(-×+1) | | 4(y-7)=12-y | | 4(y-7)=12-7 | | 3(1/3)-1=1-3x | | 6^-x=20 | | X-5+2y-10+X+y+15=180 | | 13-2c+2)=2(c+2)+3c | | -4x-21=-77 | | 3−2x−x2=0 | | 3x+9=2(3x-5)-8 | | (x+4)^2-8x=0 | | X2+1.8x-3.9=0 | | 5|9x-7|+4=19 | | 3-2x/5=3 | | 2x+4=-7-6 | | x=(3x-5)+(2x-5) | | 3^(x^2-6)=27 | | (20/x+5)+3=(2/x+5) | | 4x2−2x+7=0 | | 4x2+3x+4=0 |