2x2-16x=12x-48

Solution for 2x2-16x=12x-48 equation:

2x^2-16x=12x-48

We move all terms to the left:

2x^2-16x-(12x-48)=0

We get rid of parentheses

2x^2-16x-12x+48=0

We add all the numbers together, and all the variables

2x^2-28x+48=0

a = 2; b = -28; c = +48;
Δ = b2-4ac
Δ = -282-4·2·48
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-20}{2*2}=\frac{8}{4}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+20}{2*2}=\frac{48}{4}
=12
$