2x2-16x=96

Solution for 2x2-16x=96 equation:

2x^2-16x=96

We move all terms to the left:

2x^2-16x-(96)=0

a = 2; b = -16; c = -96;
Δ = b2-4ac
Δ = -162-4·2·(-96)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-32}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+32}{2*2}=\frac{48}{4}
=12
$