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2x^2-17x-12=0
a = 2; b = -17; c = -12;
Δ = b2-4ac
Δ = -172-4·2·(-12)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{385}}{2*2}=\frac{17-\sqrt{385}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{385}}{2*2}=\frac{17+\sqrt{385}}{4} $
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