If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-19x-33=0
a = 2; b = -19; c = -33;
Δ = b2-4ac
Δ = -192-4·2·(-33)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-25}{2*2}=\frac{-6}{4} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+25}{2*2}=\frac{44}{4} =11 $
| 736+93673k^-73849k=746464 | | 6(n+14)+9(3n-10)=27 | | -(14p-2)-8(8p-1)=10 | | 2x+9=6x-31 | | 10(n+8)-13(6-7n)=2 | | x-0,12x=1405 | | -(11x+4)+6(1-4x)=72 | | 164x-328=18x+42 | | -51=13(7-14x)+4(11x-1) | | x-0,12x=15207 | | 2n-13=19 | | -4a-6+5a=9+1-6a+5 | | -3t-1=4 | | 9u^2-7u-11=0 | | -25=-13(12x-3)-10(10-12x) | | 3n-40=20 | | f(4)=3*4-4 | | 72=12(a+3)+8(-7+10a) | | 2x-2=5x-32 | | 7x-17=x+25 | | 4-8/3x+1=3x2+5/3x+1 | | 2(11a-6)-4(9-9a)=68 | | -99=63u-36u^2 | | -11(13x-7)-8(12-3x)=100 | | 1k+(k+1)+(k+2)=4k | | x*9+28=12x*4 | | 1,5x=-11=x-1 | | 9x+17=5x+5 | | -2x+19=x+31 | | y=4×2^-3 | | 4(2x+1)=2(5x+4) | | 3-8c=65 |