2x2-20x=112

Solution for 2x2-20x=112 equation:

2x^2-20x=112

We move all terms to the left:

2x^2-20x-(112)=0

a = 2; b = -20; c = -112;
Δ = b2-4ac
Δ = -202-4·2·(-112)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-36}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+36}{2*2}=\frac{56}{4}
=14
$