2x2-21x-11=0

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Solution for 2x2-21x-11=0 equation:



2x^2-21x-11=0
a = 2; b = -21; c = -11;
Δ = b2-4ac
Δ = -212-4·2·(-11)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-23}{2*2}=\frac{-2}{4} =-1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+23}{2*2}=\frac{44}{4} =11 $

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