2x2-24x=2

Solution for 2x2-24x=2 equation:

2x^2-24x=2

We move all terms to the left:

2x^2-24x-(2)=0

a = 2; b = -24; c = -2;
Δ = b2-4ac
Δ = -242-4·2·(-2)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{37}}{2*2}=\frac{24-4\sqrt{37}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{37}}{2*2}=\frac{24+4\sqrt{37}}{4}
$